What software do I need to make cartoons?

3d scanner output image

Jimmy

I want to make animated cartoons, but am not sure what software I need. What software is best to draw the characters and backgrounds? Once I draw the characters do I then put them into Adobe Flash to make a cartoon?

Answer
You can use any of these FREE Cartoon Animation Softwares.........

Pencil : http://www.pencil-animation.org/
Pencil is an animation/drawing software for Mac OS X, Windows, and Linux. It lets you create traditional hand-drawn animation (cartoon) using both bitmap and vector graphics. Pencil is free and open source.

Synfig Animation Studio : http://synfig.org/
Synfig is a powerful, industrial-strength vector-based open-source 2D animation software package, designed from the ground-up for producing feature-film quality animation with fewer people and resources.2D Animation has traditionally been very expensive because every frame must be drawn by hand. Even with today´s digital inking and painting software, the process still relies on individuals hand-drawing each frame. This laborious task is called "tweening".Synfig eliminates the task of manual tweening, producing smooth, fluid motion without the animator having to draw out each frame individually. This allows you to produce 2D animation with fewer people while producing art of a higher quality.

Tapptoons Linetester : http://myweb.tiscali.co.uk/tapptoons/index.htm
The Tapptoons Linetester enables animators to use a scanner or video camera (with compatible capture card) to input animation images into a standard PC and edit their work, adding soundtrack and color if they wish and to output the result as a Windows AVI. Can be used for puppet animation as well as drawn animation.

eDrawings : http://www.edrawingsviewer.com/
eDrawings is a freeware utility which will give the user the power to view, create and share 3D models and 2D drawings. eDrawings offers unique capabilities like point-and-click animations that make it easy for anyone with a PC to interpret and understand 2D and 3D design data.





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How to make a java program with output a triangle of numbers?

Lindsey

Hey everyone, I'm trying to help a friend with his program as he is struggling in his java class. it has been awhile since I've used java and while I am close, the math isn't lining up.

We are both really close.

We are trying to create a triangle that looks like this if a user enters 5:
1
2 6
3 7 10
4 8 11 13
5 9 12 14 15


So far we got this:
1
2 6
3 7 8
4 8 9 11
5 9 10 12 15

Here is the code:

public static void triangle2(int n)
{

//check the input and return an error message if erronous input
if (n<1){
System.out.println("Please enter a value greater than or equal to 1.");
return;
}

int val=1;

for (int i=1; i<=n; i++)
{
System.out.printf("%3d",val);
int c = 1;
int y = i+(n-c);
for (int j=1; j<i; j++){
System.out.printf("%3d", y);
// y= y-j;
y = y+c;
c++;
}
System.out.println();
val++;
}
}

Thank you :D

Answer
Yes, you are close ... try ...

import java.util.Scanner;

public class triangle2
{
public static void triangle2(int n)
{

//check the input and return an error message if erronous input
if (n<1){
System.out.println("Please enter a value greater than or equal to 1.");
return;
}

int val=1;

for (int i=1; i<=n; i++)
{
System.out.printf("%3d",val);
int c = 1;
int y = i+(n-c);
for (int j=1; j<i; j++){
System.out.printf("%3d", y);
// y= y-j;
y = y+c;
c++;
}
System.out.println();
val++;
}
}

public static void main(String[]args) { // main function
int nsize = 0, i;

// Check for argument 1 number rows in triangle
if (args.length > 0) {
for(i=0; i<args[0].toString().length(); i++) {
if (args[0].substring(i,1).compareTo("0") >= 0 &&
args[0].substring(i,1).compareTo("9") <= 0) {
nsize = nsize;
} else if (!args[0].substring(i,1).equals("-")) {
nsize--;
}
}
if (nsize == 0) nsize = Integer.parseInt(args[0]);
}
if (nsize <= 0) {
Scanner inputscanner = new Scanner(System.in);
System.out.print("How many rows are there in your triangle? ");
nsize = inputscanner.nextInt();
}
triangle2(nsize);
} // end of main function

}

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